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#31
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#32
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I think he mean he wants each step broken down.
I don't see how that will help you blingbling unless somebody explains it all you.
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Audi humbles Porsche. A new dawn starts today. Being nice since 2007. |
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#33
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#34
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#35
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I remember doing all that and being very good at it. 2 years without maths of any sort and I REALLY need to refresh, thanks for the thread
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Audi humbles Porsche. A new dawn starts today. Being nice since 2007. |
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#36
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hope this helps. finally having a tablet comes in handy. just in case you don't trust me, mathematica's answer is attached too. |
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#37
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However, is the second derivative correct? The first two components look right but the third doesn't (looking at the non-simplified form). Should it be: (2/x^2)e^(-1/x^2)(2/x^2) or (2/x^3)e^(-1/x^2)(2/x^2)
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"In theory, theory and practice are the same. In practice, they are not." |
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#38
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Wow I am so glad I never have to take a Math course again. EvAr!!!!
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John says: so i had to dump acid into the block tank today i'm afraid to fap cause i got it on my hands |
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#39
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maths is funnnn
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#40
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John says: so i had to dump acid into the block tank today i'm afraid to fap cause i got it on my hands |
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#41
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Otherwise it is boring,difficult and annoying
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#42
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#43
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((-2/x^3)+(4/x^5))e^(-1/x^2) which is correct its the same answer given by mathematica in someone else's post. In my hurry to be done i didn't check my exponenets. |
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#44
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d/dx e^u = u'e^(u) you have it as d/dx e^u = e^(u') |
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#45
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